6/12/2023 0 Comments Atm chemistry calculator![]() What this means is that we can use the coefficients in the balanced equation to form volume relationships just as we did in the earlier Stoichiometry problems when we used the coefficients to form mole relationships.Pressure is a scalar quality reflecting how force acts on a surface. The volume-volume problems are the easiest since according to the Law of Combining Gas Volumes, gases combine at the same temperature and pressure in simple whole number of volumes. Volume to Volume Gas Stoichiometry Problems Convert 4.5 moles O 2 to liters O 2 using the PV = nRTĬonvert the 27 degrees Celsius to Kelvin: K = 27 + 273 = 300 K.Convert moles of KClO 3 to moles of O 2:ģ moles KClO 3 X 3 moles O 2 / 2 moles KClO 3 = 4.5 moles O 2.Convert 367.8 grams of given KclO 3 to moles:ģ67.8 grams KClO 3 X 1 mole KClO 3 / 122.6 grams KClO 3 = 3 moles KClO 3. ![]() How many liters of O 2 will be produced at 27 degrees Celsius and 1 atm pressure in the decomposition of 367.8 grams KClO 3?
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